[SS] Laplace Transform : $\sin^2 \Omega_0 t u(t)$
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.../Signals and Systems
$$\sin^2 t = \frac{1-\cos 2t}{2}$$ 를 이용한다. $\sin^2 \Omega_0 t$는 다음과 같이 전개가 가능함. $$\begin{aligned}\sin^2(\Omega_0 t)&=\frac{1-\cos 2\Omega_0t}{2}\\ &=\frac{1}{2}-\frac{1}{2}\cos 2\Omega_0t\end{aligned}$$ 이를 (Unilateral )Laplace transform하면 다음과 같음. $$\begin{aligned}\mathscr{L}\left[\sin^2\Omega_0 t\right]&=\mathscr{L}\left[\frac{1}{2}\right]-\mathscr{L}\left[\frac{1}{2}\cos 2\Omega_0t\right]\\ &=\..